经典算法java实现部分代码//系统拥有的初始资源数publicstaticintAVAILABLE[]={10,5,7};//系统已给每个进程分配的资源数publicstaticintALLOCATION[][]={{0,0,0},{0,0,0},{0,0,0},{0,0,0},{0,0,0}};//每个进程还需要的资源数publicstaticintNEED[][]={{7,5,3},{3,2,2},{9,0,2},{2,2,2},{4,3,3}};//每次申请的资源数publicstaticintRequest[]={0,0,0};//进程数与资源数publicstaticintM=5,N=3;intFALSE=0;intTRUE=1;publicvoidshowdata(){inti,j;System.out.print("系统可用的资源数为:/n");for(j=0;j<N;j++){System.out.print("资源"+j+":"+AVAILABLE[j]+"");}System.out.println();System.out.println("各进程还需要的资源量:");for(i=0;i<M;i++){System.out.print("进程"+i+":");for(j=0;j<N;j++){System.out.print("资源"+j+":"+NEED[i][j]+"");}System.out.print("/n");}System.out.print("各进程已经得到的资源量:/n");for(i=0;i<M;i++){System.out.print("进程");System.out.print(i);for(j=0;j<N;j++){System.out.print("资源"+j+":"+ALLOCATION[i][j]+"");}System.out.print("/n");
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