学习信息安全的入门必看30本图书!从协议工具到恶意代码的分析以及操作零碎的基本认识
2018/4/1 16:42:07 29KB 信息安全 必看书籍 30本
无论是哪种沙箱技术,总归无法和真实环境比拟,所以沙箱逃避技术在高级别病毒样本已经普遍存在,并且逃避技术也在逐步更新。
下面总结下当前的逃避技术,我分为两个特点进行分析。
·针对虚拟机检测·针对沙箱分析环境特点的对抗
2015/2/11 8:01:16 4.19MB 沙箱逃逸
操作零碎中有关进程调度的算法C++实现,是期末大型实验之一,带实验报告
2020/11/12 5:09:02 851KB 进程调度算法 操作系统
毕设做的系统,包含所有的源码,可编译运转。
2017/9/27 7:53:14 7.09MB 入侵检测
SEO界神普通的存在百度搜狗收录辅助引蜘蛛神器骷髅外链宝,你值得拥有的外链神器。
2017/6/5 4:54:39 51.19MB 骷髅侠 百度搜录 搜狗搜录
一本书上的实例,次要针对网络的协议进行分析,然后判断其中的入侵事件
2020/8/14 21:41:31 2.2MB IDS
操作系统课的实验(银里手算法)#include"malloc.h"  #include"stdio.h"  #include"stdlib.h"  #definealloclensizeof(structallocation)  #definemaxlensizeof(structmax)  #defineavalensizeof(structavailable)  #defineneedlensizeof(structneed)  #definefinilensizeof(structfinish)  #definepathlensizeof(structpath)  structallocation  {  intvalue;  structallocation*next;  };  structmax  {  intvalue;  structmax*next;  };  structavailable/*可用资源数*/  {  intvalue;  structavailable*next;  };  structneed/*需求资源数*/  {  intvalue;  structneed*next;  };  structpath  {  intvalue;  structpath*next;  };  structfinish  {  intstat;  structfinish*next;  };  intmain()  {  introw,colum,status=0,i,j,t,temp,processtest;  structallocation*allochead,*alloc1,*alloc2,*alloctemp;  structmax*maxhead,*maxium1,*maxium2,*maxtemp;  structavailable*avahead,*available1,*available2,*workhead,*work1,*work2,*worktemp,*worktemp1;  structneed*needhead,*need1,*need2,*needtemp;  structfinish*finihead,*finish1,*finish2,*finishtemp;  structpath*pathhead,*path1,*path2;  printf("\n请输入系统资源的种类数:");  scanf("%d",&colum);  printf("请输入现时内存中的进程数:");  scanf("%d",&row);  printf("请输入已分配资源矩阵:\n");  for(i=0;inext=alloc2->next=NULL;  scanf("%d",&allochead->value);  status++;  }  else  {  alloc2=(structallocation*)malloc(alloclen);  scanf("%d,%d",&alloc2->value);  if(status==1)  {  allochead->next=alloc2;  status++;  }  alloc1->next=alloc2;  alloc1=alloc2;  }  }  }  alloc2->next=NULL;  status=0;  printf("请输入最大需求矩阵:\n");  for(i=0;inext=maxium2->next=NULL;  scanf("%d",&maxium1->value);  status++;  }  else  {  maxium2=(structmax*)malloc(maxlen);  scanf("%d,%d",&maxium2->value);  if(status==1)  {  maxhead->next=maxium2;  status++;  }  maxium1->next=maxium2;  maxium1=maxium2;  }  }  }  maxium2->next=NULL;  status=0;  printf("请输入现时系统剩余的资源矩阵:\n");  for(j=0;jnext=available2->next=NULL;  work1->next=work2->next=NULL;  scanf("%d",&available1->value);  work1->value=available1->value;  status++;  }  else  {  available2=(structavailable*)malloc(avalen);  work2=(structavailable*)malloc(avalen);  scanf("%d,%d",&available2->value);  work2->value=available2->value;  if(status==1)  {  avahead->next=available2;  workhead->next=work2;  status++;  }  available1->next=available2;  available1=available2;  work1->next=work2;  work1=work2;  }  }  available2->next=NULL;  work2->next=NULL;  status=0;  alloctemp=allochead;  maxtemp=maxhead;  for(i=0;inext=need2->next=NULL;  need1->value=maxtemp->value-alloctemp->value;  status++;  }  else  {  need2=(structneed*)malloc(needlen);  need2->value=(maxtemp->value)-(alloctemp->value);  if(status==1)  {  needhead->next=need2;  status++;  }  need1->next=need2;  need1=need2;  }  maxtemp=maxtemp->next;  alloctemp=alloctemp->next;  }  need2->next=NULL;  status=0;  for(i=0;inext=finish2->next=NULL;  finish1->stat=0;  status++;  }  else  {  finish2=(structfinish*)malloc(finilen);  finish2->stat=0;  if(status==1)  {  finihead->next=finish2;  status++;  }  finish1->next=finish2;  finish1=finish2;  }  }  finish2->next=NULL;/*Initializationcompleated*/  status=0;  processtest=0;  for(temp=0;tempstat==0)  {  for(j=0;jnext,worktemp=worktemp->next)  if(needtemp->valuevalue)  processtest++;  if(processtest==colum)  {  for(j=0;jvalue+=alloctemp->value;  worktemp1=worktemp1->next;  alloctemp=alloctemp->next;  }  if(status==0)  {  pathhead=path1=path2=(structpath*)malloc(pathlen);  path1->next=path2->next=NULL;  path1->value=i;  status++;  }  else  {  path2=(structpath*)malloc(pathlen);  path2->value=i;  if(status==1)  {  pathhead->next=path2;  status++;  }  path1->next=path2;  path1=path2;  }  finishtemp->stat=1;  }  else  {  for(t=0;tnext;  finishtemp->stat=0;  }  }  else  for(t=0;tnext;  alloctemp=alloctemp->next;  }  processtest=0;  worktemp=workhead;  finishtemp=finishtemp->next;  }  }  path2->next=NULL;  finishtemp=finihead;  for(temp=0;tempstat==0)  {  printf("\n系统处于非安全状态!\n");  exit(0);  }  finishtemp=finishtemp->next;  }  printf("\n系统处于安全状态.\n");  printf("\n安全序列为:\n");  do  {  printf("p%d",pathhead->value);  }  while(pathhead=pathhead->next);  printf("\n");  return0;  }#include"string.h"#include#include#defineM5#defineN3#defineFALSE0#defineTRUE1/*M个进程对N类资源最大资源需求量*/intMAX[M][N]={{7,5,3},{3,2,2},{9,0,2},{2,2,2},{4,3,3}};/*系统可用资源数*/intAVAILABLE[N]={10,5,7};/*M个进程对N类资源最大资源需求量*/intALLOCATION[M][N]={{0,0,0},{0,0,0},{0,0,0},{0,0,0},{0,0,0}};/*M个进程已经得到N类资源的资源量*/intNEED[M][N]={{7,5,3},{3,2,2},{9,0,2},{2,2,2},{4,3,3}};/*M个进程还需要N类资源的资源量*/intRequest[N]={0,0,0};voidmain(){inti=0,j=0;charflag='Y';voidshowdata();voidchangdata(int);voidrstordata(int);intchkerr(int);showdata();while(flag=='Y'||flag=='y'){i=-1;while(i=M){printf("请输入需申请资源的进程号(从0到");printf("%d",M-1);printf(",否则重输入!):");scanf("%d",&i);if(i=M)printf("输入的进程号不存在,重新输入!\n");}printf("请输入进程");printf("%d",i);printf("申请的资源数\n");for(j=0;jNEED[i][j]){printf("进程");printf("%d",i);printf("申请的资源数大于进程");printf("%d",i);printf("还需要");printf("%d",j);printf("类资源的资源量!申请不合理,出错!请重新选择!\n");/*printf("申请不合理,出错!请重新选择!\n");*/flag='N';break;}else{if(Request[j]>AVAILABLE[j]){printf("进程");printf("%d",i);printf("申请的资源数大于系统可用");printf("%d",j);printf("类资源的资源量!申请不合理,出错!请重新选择!\n");/*printf("申请不合理,出错!请重新选择!\n");*/flag='N';break;}}}if(flag=='Y'||flag=='y'){changdata(i);if(chkerr(i)){rstordata(i);showdata();}elseshowdata();}elseshowdata();printf("\n");printf("是否继续银里手算法演示,按'Y'或'y'键继续,按'N'或'n'键退出演示:");scanf("%c",&flag);}}voidshowdata(){inti,j;printf("系统可用的资源数为:\n");printf("");for(j=0;j");}printf("\n");return0;}
2015/11/20 3:54:43 883KB 算法 银行家
历程隐藏工具历程隐藏工具历程隐藏工具历程隐藏工具历程隐藏工具历程隐藏工具历程隐藏工具历程隐藏工具历程隐藏工具历程隐藏工具历程隐藏工具历程隐藏工具
2019/3/23 5:53:58 97KB 隐藏
wpa/wpa2密码辞书破解辞书千万常用密码(153mb).txt
2017/8/26 6:51:13 153.71MB wifi 破解 密码 字典
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