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银里手算法(c语言)

上传者: lujiao87 | 上传时间:2015/11/20 3:54:43 | 文件大小:883KB | 文件类型:rar
银里手算法(c语言)
操作系统课的实验(银里手算法)#include"malloc.h"  #include"stdio.h"  #include"stdlib.h"  #definealloclensizeof(structallocation)  #definemaxlensizeof(structmax)  #defineavalensizeof(structavailable)  #defineneedlensizeof(structneed)  #definefinilensizeof(structfinish)  #definepathlensizeof(structpath)  structallocation  {  intvalue;  structallocation*next;  };  structmax  {  intvalue;  structmax*next;  };  structavailable/*可用资源数*/  {  intvalue;  structavailable*next;  };  structneed/*需求资源数*/  {  intvalue;  structneed*next;  };  structpath  {  intvalue;  structpath*next;  };  structfinish  {  intstat;  structfinish*next;  };  intmain()  {  introw,colum,status=0,i,j,t,temp,processtest;  structallocation*allochead,*alloc1,*alloc2,*alloctemp;  structmax*maxhead,*maxium1,*maxium2,*maxtemp;  structavailable*avahead,*available1,*available2,*workhead,*work1,*work2,*worktemp,*worktemp1;  structneed*needhead,*need1,*need2,*needtemp;  structfinish*finihead,*finish1,*finish2,*finishtemp;  structpath*pathhead,*path1,*path2;  printf("\n请输入系统资源的种类数:");  scanf("%d",&colum);  printf("请输入现时内存中的进程数:");  scanf("%d",&row);  printf("请输入已分配资源矩阵:\n");  for(i=0;inext=alloc2->next=NULL;  scanf("%d",&allochead->value);  status++;  }  else  {  alloc2=(structallocation*)malloc(alloclen);  scanf("%d,%d",&alloc2->value);  if(status==1)  {  allochead->next=alloc2;  status++;  }  alloc1->next=alloc2;  alloc1=alloc2;  }  }  }  alloc2->next=NULL;  status=0;  printf("请输入最大需求矩阵:\n");  for(i=0;inext=maxium2->next=NULL;  scanf("%d",&maxium1->value);  status++;  }  else  {  maxium2=(structmax*)malloc(maxlen);  scanf("%d,%d",&maxium2->value);  if(status==1)  {  maxhead->next=maxium2;  status++;  }  maxium1->next=maxium2;  maxium1=maxium2;  }  }  }  maxium2->next=NULL;  status=0;  printf("请输入现时系统剩余的资源矩阵:\n");  for(j=0;jnext=available2->next=NULL;  work1->next=work2->next=NULL;  scanf("%d",&available1->value);  work1->value=available1->value;  status++;  }  else  {  available2=(structavailable*)malloc(avalen);  work2=(structavailable*)malloc(avalen);  scanf("%d,%d",&available2->value);  work2->value=available2->value;  if(status==1)  {  avahead->next=available2;  workhead->next=work2;  status++;  }  available1->next=available2;  available1=available2;  work1->next=work2;  work1=work2;  }  }  available2->next=NULL;  work2->next=NULL;  status=0;  alloctemp=allochead;  maxtemp=maxhead;  for(i=0;inext=need2->next=NULL;  need1->value=maxtemp->value-alloctemp->value;  status++;  }  else  {  need2=(structneed*)malloc(needlen);  need2->value=(maxtemp->value)-(alloctemp->value);  if(status==1)  {  needhead->next=need2;  status++;  }  need1->next=need2;  need1=need2;  }  maxtemp=maxtemp->next;  alloctemp=alloctemp->next;  }  need2->next=NULL;  status=0;  for(i=0;inext=finish2->next=NULL;  finish1->stat=0;  status++;  }  else  {  finish2=(structfinish*)malloc(finilen);  finish2->stat=0;  if(status==1)  {  finihead->next=finish2;  status++;  }  finish1->next=finish2;  finish1=finish2;  }  }  finish2->next=NULL;/*Initializationcompleated*/  status=0;  processtest=0;  for(temp=0;tempstat==0)  {  for(j=0;jnext,worktemp=worktemp->next)  if(needtemp->valuevalue)  processtest++;  if(processtest==colum)  {  for(j=0;jvalue+=alloctemp->value;  worktemp1=worktemp1->next;  alloctemp=alloctemp->next;  }  if(status==0)  {  pathhead=path1=path2=(structpath*)malloc(pathlen);  path1->next=path2->next=NULL;  path1->value=i;  status++;  }  else  {  path2=(structpath*)malloc(pathlen);  path2->value=i;  if(status==1)  {  pathhead->next=path2;  status++;  }  path1->next=path2;  path1=path2;  }  finishtemp->stat=1;  }  else  {  for(t=0;tnext;  finishtemp->stat=0;  }  }  else  for(t=0;tnext;  alloctemp=alloctemp->next;  }  processtest=0;  worktemp=workhead;  finishtemp=finishtemp->next;  }  }  path2->next=NULL;  finishtemp=finihead;  for(temp=0;tempstat==0)  {  printf("\n系统处于非安全状态!\n");  exit(0);  }  finishtemp=finishtemp->next;  }  printf("\n系统处于安全状态.\n");  printf("\n安全序列为:\n");  do  {  printf("p%d",pathhead->value);  }  while(pathhead=pathhead->next);  printf("\n");  return0;  }#include"string.h"#include#include#defineM5#defineN3#defineFALSE0#defineTRUE1/*M个进程对N类资源最大资源需求量*/intMAX[M][N]={{7,5,3},{3,2,2},{9,0,2},{2,2,2},{4,3,3}};/*系统可用资源数*/intAVAILABLE[N]={10,5,7};/*M个进程对N类资源最大资源需求量*/intALLOCATION[M][N]={{0,0,0},{0,0,0},{0,0,0},{0,0,0},{0,0,0}};/*M个进程已经得到N类资源的资源量*/intNEED[M][N]={{7,5,3},{3,2,2},{9,0,2},{2,2,2},{4,3,3}};/*M个进程还需要N类资源的资源量*/intRequest[N]={0,0,0};voidmain(){inti=0,j=0;charflag='Y';voidshowdata();voidchangdata(int);voidrstordata(int);intchkerr(int);showdata();while(flag=='Y'||flag=='y'){i=-1;while(i=M){printf("请输入需申请资源的进程号(从0到");printf("%d",M-1);printf(",否则重输入!):");scanf("%d",&i);if(i=M)printf("输入的进程号不存在,重新输入!\n");}printf("请输入进程");printf("%d",i);printf("申请的资源数\n");for(j=0;jNEED[i][j]){printf("进程");printf("%d",i);printf("申请的资源数大于进程");printf("%d",i);printf("还需要");printf("%d",j);printf("类资源的资源量!申请不合理,出错!请重新选择!\n");/*printf("申请不合理,出错!请重新选择!\n");*/flag='N';break;}else{if(Request[j]>AVAILABLE[j]){printf("进程");printf("%d",i);printf("申请的资源数大于系统可用");printf("%d",j);printf("类资源的资源量!申请不合理,出错!请重新选择!\n");/*printf("申请不合理,出错!请重新选择!\n");*/flag='N';break;}}}if(flag=='Y'||flag=='y'){changdata(i);if(chkerr(i)){rstordata(i);showdata();}elseshowdata();}elseshowdata();printf("\n");printf("是否继续银里手算法演示,按'Y'或'y'键继续,按'N'或'n'键退出演示:");scanf("%c",&flag);}}voidshowdata(){inti,j;printf("系统可用的资源数为:\n");printf("");for(j=0;j");}printf("\n");return0;}

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评论信息

  • baidu_31731493:
    很好。直接拿来当作业了。一分值的给2016-04-05
  • 西瓜果果:
    很好。直接拿来当作业了。一分值的给2016-04-05
  • u010377279:
    真不错哈,正好是我们操作系统课需要的。感谢楼主啊。2014-06-19
  • dongmengjiao:
    真不错哈,正好是我们操作系统课需要的。感谢楼主啊。2014-06-19
  • aqheaven:
    不错,是个好资料2014-05-19
  • aqheaven:
    不错,是个好资料2014-05-19
  • ieyqss:
    功能基本实现值得学习2013-05-29
  • ieyqss:
    功能基本实现值得学习2013-05-29

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